Hacker releases source code for iOS 8.4.1 jailbreak


iOS 8.4.1 jailbreak

Luca Todesco, a student and “exploit developer” based in Italy, has released the source code for an iOS 8.4.1 jailbreak — the latest release of iOS 8. The code will likely lead to an iOS 8.4.1 jailbreaking tool for all.

Todesco, who discovered two zero-day vulnerabilities in OS X Yosemite back in August, uploaded the code to GitHub with the codename “Yalu.” The accompanying description reads, “source code of an incomplete iOS 8.4.1 jailbreak.”

“The incomplete bit refers to the fact that the source code of the jailbreak is limited to tethered boot only,” explains RedmondPie“The reason given for this is that the untethered code doesn’t belong to Tedesco hence he can’t make it available for everyone just yet.”

The source code alone gives you the ability to jailbreak iOS 8.4.1 if you know what you are doing, which in turns provides OpenSSH access. However, note that because this jailbreak is incomplete, it does not install Cydia, and it is recommended you don’t install it manually.

The code isn’t a whole lot of use to the average iOS user for now, then, but it’s only a matter of time before someone puts it to good use. Even Todesco himself has teased on Twitter that “yalu for i6 [iPhone 6] will be out very soon.”

In the meantime, it is advised that you stay away from the source code if you aren’t completely sure how to use it. You could end up doing great damage to your iOS device by attempting to jailbreak it yourself.

If you’re yet to upgrade to iOS 9 because you want to jailbreak, it looks like your patience could soon pay off. But remember not to update in the meantime, because there is no way back to iOS 8.1.4 once you do so.

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